Re: Not using cached version
| From: | Stut | Date: | Wed, 30 Aug 2006 10:02:15 +0000 |
| Subject: | Re: Not using cached version | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-241217@lists.php.net to get a copy of this message | ||
Peter Lauri wrote:
I have some images stored in a database (only file name and other relevant information, rest stored in file system). I use the following html to access them: <img src='image.php?imageid=123' /> At some pages I have the same image, so that tag will be seen on multiple places on the same page. So what I am curious is why all of the different images are loaded separately, instead of just recognizing that they are the same and use a cache version? This is the code that do all the work: Header ("Content-type: $image_type"); readfile("files/$image"); I am a little bit lost here; kick me in the right direction if you can :)Probably because the browser sees the ? in the URL, thinks dynamic and doesn't cache the result. You can set caching headers to get around this (Google for it), or if you want *all* browsers to do it right, even the poorly implemented ones, you could modify the URL so it doesn't have the ?. I do this using the Apache MultiViews option and a URL similar to /image/123.gif. That actually runs /image.php which pulls the REQUEST_URI server variable apart to get the required image. Do both and you should be good for all browsers. -Stut