Re: Re: Miserable escape string problem

The escaping works fine for me.. using the code: $var1 = 1; $var2 = 3; echo "\$var1: $var2"; print "\$var1: $var2"; print ("\$var1: $var2"); All output: $var1: 3 as expected. Is there a way to re-define the escape character or something? I can't think of why that wouldn't escape the $ properly. = = = Original message = = = Well Kae, if you reply 3 times let me also reply you once. What you try to suggest is a workaround. A workaround should not be needed for such a basic thing. Ever. The point is, \ should escape only the , just like it does when you escape a variable like this "\$var1" In this case, \ only escapes the $. Even then, why does it output the \? Try this: ========================================================= $var1 = 1; $var2 = 2; print("\$var1: $var2"); ========================================================= It will output: \1: 2 Why the \? Isn't it an escape character. If you try to get me thinking that this is normal behaviour, let's agree to disagree. PS: I'd like to see an insider comment on this, eventually explain the thought behind this implementation. Kae Verens wrote: > because $var1 is a valid syntactical construct? > > try this instead: > ''.$var1.': '.$var2.'' > > Kae ___________________________________________________________ Sent by ePrompter, the premier email notification software. Free download at http://www.ePrompter.com.