Re: Can i take the variable name in a function?
| From: | Andy Hultgren | Date: | Wed, 11 Oct 2006 16:15:59 +0000 |
| Subject: | Re: Can i take the variable name in a function? | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-242987@lists.php.net to get a copy of this message | ||
Would something like this work?
Definition:
function example($$ex) {
echo "Variable Name is $ex";
}
example($ball);
I'm fairly new to php and not so familiar with variable variables, but I
thought I'd throw it out there as a thought!
Andy
On 10/11/06, Jochem Maas <jochem@iamjochem.com> wrote:
Jônata Tyska Carvalho wrote: How can i take the variable name inside a function, ex: definition: function example( $ex ){ echo "Variable Name is $ex "; // how to do this? } use: example($ball); output: Variable Name is ball; another: example($sportCar); output: Variable Name is sportCar; is that possible? no. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php