Re: Re: [PHP] <OPTION

...and if you wanted to go an extra step you could try an alternate syntax of the exact same code: <?php foreach (range(1, 31) as $day)

       print '<option value="' . $day . '"' . ($selected_day_of_month

== $day ? ' selected' : '') . '>' . $day . '</option>'; ?> Either way, Stut is correct. Don't type this out 31 times unless you really really really like to type. ;-) - Joe On 10/25/06, Stut <stuttle@gmail.com> wrote:

Ron Piggott (PHP) wrote: I am creating a form right now. I am using the html SELECT tag. <SELECT NAME="day_of_month"> The most number of days in a month is 31 I want the output to be <OPTION SELECTED>## based on the value of $selected_day_of_month variable. For the days of the month where the number is not selected the output I am desiring is <OPTION>1 <OPTION>2 etc. to be generated through PHP code I already have a value the user submitted in a variable named $selected_day_of_month from being stored in a mySQL table Does anyone know how to do this in a few commands? I am wanting to simplify <? if ( $selected_day_of_month == "1" ) } <OPTION SELECTED>1 } ELSE { <OPTION>1 } if ( $selected_day_of_month == "2" ) } <OPTION SELECTED>2 } ELSE { <OPTION>2 } ?> etc. Dang that's painful!! Try this... <?php

     foreach (range(1, 31) as $day)
     {
         print '<option value="'.$day.'"';
         if ($selected_day_of_month == $day)
             print ' selected';
         print '>'.$day.'</option>';
     }

?> I added a value to the options (you knew that was missing right?). Obviously you need to output the <select ...> and </select> outside this loop. -Stut -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php