Re: http_build_query ... argh

Jochem Maas wrote:

Arpad Ray wrote:

return preg_replace('#%5[bd](?=[^&]*=)#ei', 'urldecode("\0")', $s);

could you explain your regexp - I'd like to replace my version with your (if for no other reason than that shorter code is easier to read than longer code!) BUT until I really understand your regexp I'd feel 100% comfortable making the replacement. Basically, if we find a '=' before a '&' then we know we're in the key.

The (?=) is a positive assertion, which says that the bracket must be followed by a '=', optionally with any characters except '&' in between. Here's the pattern with comments: ~

   %5[bd]      # the bracket
   (?=         # must be followed by
       [^&]*   # any characters except "&"
       =       # then a "="

) ~eix Regards, Arpad