Re: Error with array and include
| From: | Fernando M. M. | Date: | Tue, 05 Dec 2006 15:45:50 +0000 |
| Subject: | Re: Error with array and include | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-245526@lists.php.net to get a copy of this message | ||
T.Lensselink,
Ok, problem solved. I didn't realized that i was using the same variable.
Thanks for the help!
T.Lensselink escreveu:
How can you use an array as string in the include statement and two lines lower as array? Think it echo's 'S' because it see's $lang as a string and not an array. On Tue, 05 Dec 2006 13:11:12 -0200, "Fernando M. M." <stormrider@tifacil.com.br> wrote:Hi, I'm having a strange problem when trying to show a array after its value was defined on a file that was included. Something like this: <?php$lang = 'pt_BR';include('lang/'. $lang .'/login.php');echo $lang['Username'];?> On the file lang/pt_BR/login.php i have this... <?php$lang['Username'] = 'Usuário';?> But the result of the first script is 'S' (without quotes). If i change lang/pt_BR/login.php to <?php$lang['Username'] = 'Usuário';echo $lang['Username'];?> I get 'Usuário' (without quotes again). Why does this happens? Thanks, Fernando. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php