Re: Ensuring that variable contains a number

# dotancohen@gmail.com / 2006-12-06 23:51:45 +0200: > >> How can I ensure that a variable contains a postive integer number? > >> I'm currently using this code: > >> > >> $number=(10000-$number); > >> $number=(10000-$number); > >> if ( $number<1 ) { $number=1; } > >> > >> But I'm sure that there is a better way. What would that be? > Thanks. As the 'number' is used in a for loop, it actually is alright > if it is a float. I just added a check that the number is indeed >=1, > otherwise I set it to 1. Good enough for this project, anyway... :) $number = max(intval($number), 1); -- How many Vietnam vets does it take to screw in a light bulb? You don't know, man. You don't KNOW. Cause you weren't THERE. http://bash.org/?255991