Re: Memory/Object question

Bug Hunter wrote: > If I have an object in an array and do the following: > > obj2 = new obj; > > obj["1"] = obj2; > > If obj["1"] already existed, what happens to it? does it lay around > consuming memory, or is it destroyed? > > Or does the data in the object get copied? If not, can I make the data > get copied so I don't eat up memory, without doing a variable at a time? First, I guess you meant $obj2, $obj[1] and obj in your snippet, cause variables begin with $ in php . The data get copied. At least in current versions of php3 and php4. That means you will get two separate objects of the class obj, $obj[1] will be a copy of $obj2, and hense you'll eat twise as much memory. If you change something in $obj[1], it won't affect $obj2. If you want to deal with one instance of the class obj, references would help: $obj2 = new obj; $obj[1] = &$obj2; Now you have a reference to $obj2 in $obj[1], not a copy of $obj2, and if you deal with $obj[1], you'll actuelly deal with $obj2. -- Best regards, Max A. Derkachev mailto:kot@books.ru Symbol-Plus Publishing Ltd. phone: +7 (812) 265-0054, 265-1228, phone/fax: 567-8775 http://www.Books.Ru -- All Books of Russia