Re: question about str_replace function
| From: | Jochem Maas | Date: | Mon, 08 Jan 2007 13:31:31 +0000 |
| Subject: | Re: question about str_replace function | ||
| References: | 1 2 3 4 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-246754@lists.php.net to get a copy of this message | ||
Roman Neuhauser wrote:
> # jochem@iamjochem.com / 2007-01-08 11:35:06 +0100:
>> Dick Jiang wrote:
>>> I think you'd better use regular expression to replace the word
>> agreed - only it a serious dive in the deep end of regexps - the OP may
>> have to use a negative lookahead assertion, something like:
>>
>> $string="avenue 1, ave 1 both have av+e :-)";
>> $words = preg_replace("#\\bave(?!nue)#", "avenue", $string);
>
> That'll also make "average" into "avenuerage". A word-boundary
> assertion
> should (admittedly, I didn't check) be fine on both sides: '#\bave\b#'.
I think you are correct.
>