Re: Re: [BULK] [PHP] Use array returned by function directly?

Roman Neuhauser wrote:

# turnermm02@shaw.ca / 2007-01-29 10:12:25 -0600:

Roman Neuhauser wrote:

    
# neuhauser@sigpipe.cz / 2007-01-29 15:27:21 +0000:
      
# crash

#assert(2 == returns_array()['c']);

        # still crash

#assert(2 == returns_array()['c']);

s/crash/syntax error/

You can do this in Perl: my $c = (fn(@a))[2];

Not to mention C++, Python, or quite a few other languages.

But in PHP, this is a syntax error: $c = (fn($a))[2];

Well, DUH! THat's what the OP was curious about: why is it an error?

Also, it's not clear what the original syntax is meant to do:

       explode($needle, $array)[3]
explode() takes a string and converts it to an array based on the separator expression.  This might make sense:

explode($needle, $array[3]) where $array[3] is a string. But explode($needle, $array), it turns out, simply returns the string "Array".

Not at all! Watch this: <?php $array = 'O M F G'; $needle = ' '; assert(array('O', 'M', 'F', 'G') == explode($needle, $array)); ?> I thought the issue was this: $array = 'O M F G'; $needle = ' '; $array_2 = array('O', 'M', 'F', 'G'); assert($array == explode($needle, $array_2)); -- _____________________ Myron Turner http://www.room535.org http://www.bstatzero.org http://www.mturner.org/XML_PullParser/