Re: ereg() problem

jekillen wrote:

Hello php list; I am having trouble with ereg(). The following is the problem code $x = ereg("<route name='$to' x='../(.*)/in' rec='.*' />", $get_route, $m); do we need to break out of the text to include the $to variable??

testing $route I get: do you mean $get_route?

$route = $m[1]; print $route.'<br>'; jk/in' rec='a_378e6dc4.xml' /> (out put of print) Is this an example of th input?

What does an actual line of $get_route look like? do a var_dump($m); and show output

jk is all I am looking for but is it greed that is missing the forward slash and the single quote? It seems like every time I do this I have to monkey around with it until I get what I want. I have even changed the formatting of files just so a regular expression would work without this sort of trial and error. Is there a way I can turn off greed in php's regex? I am using php v5.1.2 with Apache 1.3.34 Thanks in advance. JK

or better yet, try this I am assuming on the actual structure of $get_route but the following return to me $match[1] = '../jk' $to = 'something'; $get_route = "<route name='something' x='../jk/in' rec='998asdf' />"; preg_match("|<route name='".$to."' x='(\.\./.*)/in' rec='.*' />|", $get_route, $matches); var_dump($matches); -- Enjoy, Jim Lucas Different eyes see different things. Different hearts beat on different strings. But there are times for you and me when all such things agree. - Rush