Re: Year
| From: | chetan rane | Date: | Fri, 02 Feb 2007 15:29:46 +0000 |
| Subject: | Re: Year | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-248198@lists.php.net to get a copy of this message | ||
HI Dan
try this this should work 100%;
echo "<select>";
for ($y=0;$y<=10;$y++) {
$years=date('Y')+$y;
$short_years=date('y')+$y;
printf("<option value=\"%02d\">%d</option>",$short_years,$years);
}
echo "</select>";
On 2/2/07, Dan Shirah <mrsquash2@gmail.com> wrote:
Hello all, I am trying to populate a dropdown list to contain the current year to 10 years in the future. Below is the code I'm using: <?PHP for ($y=0;$y<=10;$y++) { $years=date <http://php.net/date>('Y')+$y; $short_years=date <http://php.net/date>('y')+$y; echo "$short_years"; echo "<option value=\"$short_years\">$years</option>"; } ?> I want the selection value to be 2007, 2008, 2009, 2010.... and the $years accomplishes this. Howeverm I want the option value to be the two digit year ex. 07, 08, 09, 10...the $short_years semi accomplishes this....instead of getting 07, 08, 08, 10 I get 7, 8, 9, 10...how can I get it to output the two year for 07, 08, 09 without it cutting off the zero? Reagrds, Dan-- Have A plesant Day Chetan. D. Rane Location: Pune , India Contact: +91-9890792762 otherID: chetscool@yahoo.com chetrane@rediffmail.com