RE: [PHP] Javascript and $_POST

> -----Original Message----- > From: Dan Shirah [mailto:mrsquash2@gmail.com] > Sent: Wednesday, February 07, 2007 4:35 PM > To: php-general > Subject: [PHP] Javascript and $_POST > > I have a form that uses Javascript to validate form field entries, and if > they are incorrect it returns an error to the user. > > After the Javascript processing is complete, it submits the form to my > save > page. However it seems that once the processing is complete and it passes > to > the save page, none of my $_POST variables are being passed. > > Is this normal, or is there a work around for it? > > My Javascript has multiple checks. Below is a very condensed version: > > <script language="JavaScript"> > function checkForm() { > > if (inputForm.cc_phone_number.value == "") { > alert( "Please enter a phone number." ); > inputForm.cc_phone_number.focus(); > return; > } > > document.Submit.submit(); > } > </script> > > And this is my Save option at the bottom of my page > > <form name="Submit" action="save.php" method="post" > enctype="multipart/form-data"> > <table align="center" border="0" cellpadding="0" > cellspacing="0" > width="680"> > <tr> > <td width="64" align="left"><a > href="javascript:checkForm()" > title="Save">Save</a></td> > </tr> > </table> > </form> > > When I click on save, it does go thru all the checks correctly and prompts > to enter info if anything is left out. It then passes me to the > save.phppage as it should, but all of my $_POST('XXXXX') values come > in blank. From the looks of it, you have two forms - one called "Submit" and one called "inputForm". You need to submit the "inputForm" for the values to be passed to the processing page. document.inputForm.submit(); HTH, Brad