Re: 2 errors I can not understand

I retract my statement. I think I spoke too quickly. I think I don't fully understand the code (can't pay attention right now for some reason), and I talked too quick. I do think it has to do with the while loop though, as that is where it seems to be dying. ----- Original Message ---- From: Matt Carlson <saryon@swbell.net> To: Jonathan Kahan <jonathan@estrintech.com>; php Lists <php-general@lists.php.net> Sent: Tuesday, March 13, 2007 5:12:03 PM Subject: Re: [PHP] 2 errors I can not understand I think you have an issue with the line while($d<$s) when it comes to the number 3. $d will NEVER be < $s if $s = 3. I think you want $d<=$s?? Or maybe a switch for the number 3? ----- Original Message ---- From: Jonathan Kahan <jonathan@estrintech.com> To: php Lists <php-general@lists.php.net> Sent: Tuesday, March 13, 2007 4:30:45 PM Subject: [PHP] 2 errors I can not understand Hi all, Please see my output below followed by the code. I have been trying for some to figure out why 1) I can not get a line feed to work in the web page that i am using to display the output as I am not running from the commad line 2) Why my loop is only executing 3 times when i want it to execute 50 Any help would be greatly appreciated. Jonathan The next line is all that displays on the output html page: Output: The number 0 is 0 The number 1 is 0 The number 2 is 1 The number 3 is 1 php script: <html> <body> <?php for ($k=0;$k<50;$k++) { echo ("The number ".$k." is ".isprime($k)); echo "\r\n"; } function isprime ($s) { $a="2"; switch ($s) { case "0": $a="0"; break; case "1": $a="0"; break; case "2": $a="1"; break; default: $d=3; while ($d<$s) { if ($s%$d=0) { $a="0"; } $d+=2; } } if ($a=="2") { $a="1"; } return $a; } ?> </body> </html> "tjon2.php" 78L, 447C written -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php