Re: downloading an image

Ross wrote: > tthe image does not display although it exists in the table 'images' > > > This calls the download script > > > <? > $property_id = $_SESSION['property_id'] ; > $query = "SELECT * FROM images WHERE property_id='$property_id'"; > $result = mysql_query($query); > while($row = mysql_fetch_array($result, MYSQL_ASSOC)) > { > > echo $id= $row['id']; > echo $title= $row['title']; > $link = "download.php?id=$id"; > } what do you see when you stick the src url in the address bar of your browser? and what response headers do you get from the download.php? > ?> > <img src="<?php echo $link; ?>"/> > > > > this is the download script > > id = $_GET['id']; $id = $_GET['id']; ^ | \- missing $ ??? and then your not doing any input cleaning: if (!isset($_GET['id']) || (($id = intval($_GET['id'])) < 1)) die('eat **** and die'); > $query = "SELECT name, type, size, content FROM images WHERE id ='$id'"; > > $result = mysql_query($query) or die(mysql_error()); > list($name, $type, $size, $content) = mysql_fetch_array($result); > > header("Content-length: $size"); > header("Content-type: $type"); > > echo $content; and does $content actually contain image data? > > exit; >