RE: [PHP] how to get var name and value from function?

On 14 April 2007 13:16, Afan Pasalic wrote: > Tijnema ! wrote: > > On 4/14/07, Afan Pasalic <afan@afan.net> wrote: > > > function value2var($array, $print=0) > > > { > > > foreach ($_POST as $key => $value) > > > > I think you should change above line to : > > > > foreach ($array as $key => $value) > yup! it's print error. I meant $array. > > > { > > > ${$key} = $value; > > > echo ($print ==1) ? $key.': '.$value.'<br>'; // > > > to test > > > results and seeing array variables and values > > > } > > > } > > > > > > value2var($_POST, 1); > > > > > > but, I don't know how to get info from function back to > > > script?!?!? :-( > > > > Uhm, it's not even possible when you don't know the keys i believe. > after 2 hours of testing and research I realized this too, but want > to be sure. :-( If you really *must* do this yourself (but others have pointed out the folly of it), this would do it: function value2var($array) { foreach ($array as $key => $value) { $GLOBALS['$key'] = $value; } } ... or, alternatively, rather than defining you own function, use extract() (http://php.net/extract) with one of the overwrite safety options to avoid blobbing existing variables. Personally, I'd never do this in any form -- if I do it at all, I extract specific indices of the array with code like: foreach (array('name', 'address', 'email', 'setting1', 'setting2') as $key): $GLOBALS[$key] = $array[$key]; endforeach; ... making certain, of course, that those values get properly validated elsewhere. Cheers! Mike --------------------------------------------------------------------- Mike Ford, Electronic Information Services Adviser, Learning Support Services, Learning & Information Services, JG125, James Graham Building, Leeds Metropolitan University, Headingley Campus, LEEDS, LS6 3QS, United Kingdom Email: m.ford@leedsmet.ac.uk Tel: +44 113 812 4730 Fax: +44 113 812 3211 To view the terms under which this email is distributed, please go to http://disclaimer.leedsmet.ac.uk/email.htm