RE: [PHP] echo date('Y-m-d', $mydata->timestamp);
| From: | Buesching, Logan J | Date: | Mon, 23 Apr 2007 00:54:37 +0000 |
| Subject: | RE: [PHP] echo date('Y-m-d', $mydata->timestamp); | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-253504@lists.php.net to get a copy of this message | ||
You are misunderstanding what timestamp means. The value of a timestamp
is from UNIX epoch http://en.wikipedia.org/wiki/Unix_time. It is
calculated by the number of seconds after January 1st, 1970. Also note,
that you are overflowing the integer, which is giving you a
http://en.wikipedia.org/wiki/Year_2038_problem
Y2K38 problem.
If you want the UNIX timestamp of 4/19/2007 16:21:23, you can do
mktime(16,21,23,4,19,2007);
(http://us.php.net/manual/en/function.mktime.php).
-Logan
-----Original Message-----
From: John Taylor-Johnston
[mailto:John.Taylor-Johnston@cegepsherbrooke.qc.ca]
Sent: Sunday, April 22, 2007 2:05 AM
To: PHP-General
Cc: John Taylor-Johnston
Subject: [PHP] echo date('Y-m-d', $mydata->timestamp);
$mydata->timestamp = "20070419162123";
echo date('Y-m-d', $mydata->timestamp);
result: 2038-01-18
?? What is wrong?? Should be 2007-04-19?
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