Re: a value of variable as a name of variable

I'm not sure if I know the cause of your problem, but based on the syntax of what you provided in your email, you need to do this instead: $quality[1] = "weight"; $vl_hod = $quality[1]; echo $vl_hod; This will produce an output like: weight Your mistake was including $quality[1] in quotes, which tells PHP it's a string, not a variable or array. Hope this helps, Andrew Elliston > I have variable with this value: > $quality[1]="weight"; > $vl_hod="$quality[1]"; > > And I want use the value(!!) of variable $vl_hod as a name of > variable for the next use. Is it possible to do it? > > For example: > ???echo $vl_hod;???? > I want that the output of "echo" was the value "weight" and > no the value "$quality[1]". ------------------------------------------------ Drew's Pad <http://www.elliston.net/drew/> ------------------------------------------------