Re: showing source

yup, highlight_file($file_name) is your magical answer. http://ca.php.net/highlight_file Make sure this function will only access specific directories. -- itoctopus - http://www.itoctopus.com ""M.Sokolewicz"" <tularis@php.net> wrote in message news:464D716B.7040702@php.net... > Why don't you use: > highlight_file(__FILE__) ? > > - tul > > James Lockie wrote: >> This almost works but all my < and > are replaced with "". >> >> // open this file to show the source >> if (($fh = fopen( __FILE__, 'r' )) === FALSE){ >> die ('Failed to open source file (' . $_FILE_ . ') for >> reading!'); >> } else { >> $tags = array( "<", ">" ); >> $safe_tags = array( "\\<", "\\>" ); >> >> print "<pre>\n"; >> >> // read the file line by line >> while (! feof( $fh )) { >> $currentLine = fgets( $fh, 255 ); >> $noTags = str_replace( $tags, $safeTags, $currentLine ); >> print $noTags; >> } >> >> fclose( $fh ); >> print "</pre>\n"; >> }