Re: Re: find (matching) person in other table

David Giragosian wrote:

On 5/31/07, Afan Pasalic <afan@afan.net> wrote:

Jared Farrish wrote:

On 5/30/07, Afan Pasalic <afan@afan.net> wrote: email has to match "in total". sales@abc-comp.com and

info@abc-comp.com

are NOT the same in my case. thanks jared,

If you can match a person by their email, why not just SELECT by email only (and return the persons information)?

'cause some members can be added to database by administrator and maybe they don't have email address at all. or several memebers can use the same email address (sale@abc-company.com) and then macthing last name is kind of "required". that's how it works now and can't change it.

Consider, as well, that each time you're calling a database, you're slowing down the response of the page. So, while making a bunch of small calls might not seem like that much, consider: ||||||| x ||||||| ||||||| a ||||||| ||||||| b ||||||| Versus ||||||| x, a, b ||||||| The letters represent the request/response data (what you're giving to get, then get back), and the pipes (|) are the overhead to process, send, receive (on DB), process (on DB), send (on DB), receive, process, return to

code.

The overhead and latency used to complete one request makes it a

quicker,

less "heavy" operation. If you did the first a couple hundred or

thousand

times, I would bet your page would drag to a halt while it loads...

agree. now, I have to figure it out HOW? :-) I was looking at levenshtein, though, I think the richard's solution is just enough: select member_id, first_name, last_name, email, ..., (5*(first_name='$first_name) + 2*(first_name='$first_name')) as score from members where score > 0 though, I'm getting error: "Unknown column 'score' in where clause"?!? thanks jared.

Try using the keyword 'having' rather than 'where'. You can't use an alias in a where clause. David Yup. that works! :-)

Thanks David