Re: returning the index number part2
| From: | Jim Lucas | Date: | Tue, 05 Jun 2007 16:33:36 +0000 |
| Subject: | Re: returning the index number part2 | ||
| References: | 1 2 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-256108@lists.php.net to get a copy of this message | ||
Robert Cummings wrote:
On Tue, 2007-06-05 at 17:16 +0100, blueboy wrote:-- Jim Lucas "Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them." Twelfth Night, Act II, Scene V by William Shakespeareif I have an array of 3 images <table class="signup_table"> <tr> <td> 1.</td> <td><input name="userfile[]" type="file"></td> </tr> <tr> <td> 2.</td> <td><input name="userfile[]" type="file"></td> </tr> <tr> <td>3.</td> <td><input name="userfile[]" type="file"> </td> </tr> </table How do I access the filename? Like this? echo $fileName1 = $_FILES['userfile']['name'][0]; echo $fileName2 = $_FILES['userfile']['name'][1]; echo $fileName3 = $_FILES['userfile']['name'][2];No, like this:echo $fileName1 = $_FILES['userfile'][1]['name']; echo $fileName2 = $_FILES['userfile'][2]['name']; echo $fileName3 = $_FILES['userfile'][3]['name'];Cheers, Rob. I suggest to the op that they use print_r() on $_FILES and all will be revealed