Re: Re: Previous and Next Month and Year

Hi Vlad, Thank you for taking the time to help me. The code: $prev_month = date('F Y', mktime(0, 0, 0, 0, date('m') - 6, date('Y'))); $next_month = date('F Y', mktime(0, 0, 0, 0, date('m') + 6, date('Y'))); echo "$prev_month <br /> \n"; echo "$next_month <br /> \n"; Generates: November 2006 December 2006 The $prev_month value seems correct, but the $next_month value should be: December 2008 Do you see my mistake? Keith ----- Original Message ----- From: "Vlad Vlasceanu" <vvvlad@sbcglobal.net> To: <php-general@lists.php.net> Sent: Sunday, June 17, 2007 12:13 AM Subject: [PHP] Re: Previous and Next Month and Year

time() returns a unix timestamp of the current moment in time (now), so in effect you are adding or subtracting 6 seconds to that. calling: date('m/d/Y', time()); is the same as calling: date('m/d/Y'); On the other hand: mktime(hour, minute, second, month, day, year) generates a timestamp such that: mktime(0, 0, 0, date('d'), date('m') + 6, date('Y')); would generate a date timestamp 6 months in the future. or mktime(0, 0, 0, 0, date('m'), date('Y')); would generate last day from last month this year. Word of wisdom: don't rely solely on timestamp calculations e.g. now + 24 hours and so on, because you may need to take into account daylight savings times and such otherwise your calculations may be off. Vlad Keith Spiller wrote:

Hi, RE: Previous and Next Month and Year This is my code: $next_month = date('F Y', time()+$month); $prev_month = date('F Y', time()-$month); echo "$prev_month <br /> \n"; #Result "June 2007" echo "$next_month <br /> \n"; #Result "June 2007" What I am trying to do is get the month and year based upon a + or - $month value. The variable $month being "6" for the month of June of the present year of 2007. For example ($month -7) would be December 2006, and ($month +7) would be January 2006. Please help... Thank you. Keith

-- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php