Re: Date
| From: | Dan Shirah | Date: | Wed, 20 Jun 2007 14:06:34 +0000 |
| Subject: | Re: Date | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-257490@lists.php.net to get a copy of this message | ||
If you are pulling $start_date from a database, depending on the format you
could use something like the following:
Assuming the data is 20070215.
Connect and query your database, get the result and assign it to a variable.
$start_date = $my_result_row['start_date'];
$start_year = substr($start_date, 0, 4);
$start_month = substr($start_date, 4, 2);
$start_day = substr($start_date, 6, 2);
Now you will have variables for the entire date, the year, the month and the
day to play around with however you want.
On 6/20/07, Fredrik Thunberg <thunis@webguidepartner.com> wrote:
Ron Piggott skrev: How do I break $start_date into 3 variables --- 4 digit year, 2 digit month and 2 digit day? $start_year = ; $start_month = ; $start_day = ; Of course depending on what $start_date looks like, but this should work most of the time: $timestamp = strtotime( $start_date ); $start_year = date( "Y", $timestamp ); $start_month = date( "m", $timestamp ); $start_day = date( "d", $timestamp ); /T -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php