RE: [PHP] Optional parameters in functions....

From: Date: Fri, 17 Nov 2000 03:19:18 +0000
Subject: RE: [PHP] Optional parameters in functions....
Groups: php.general 
Request: Send a blank email to php-general+get-25857@lists.php.net to get a copy of this message
function name ($one = "", $two="") { if ($one !="") { print "one"; } if ($two !="") { print "two"; } } ? name(); ? name ("yup"); one ? name ("","yup); two ? name ("yup","yup"); onetwo -----Original Message----- From: John LYC [mailto:john@edlabs.com] Sent: November 17, 2000 11:17 AM To: PHP List Subject: [PHP] Optional parameters in functions.... hey....... how do i declared a function where parameters are optional??? function name(one,two).... { if(one).... if(two)... } when calling, name(); is still valid.... john -- PHP General Mailing List (http://www.php.net/) To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net For additional commands, e-mail: php-general-help@lists.php.net To contact the list administrators, e-mail: php-list-admin@lists.php.net

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