Re: Php code in html buttons

From: Date: Wed, 11 Jul 2007 09:07:58 +0000
Subject: Re: Php code in html buttons
References: 1  Groups: php.general 
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Hello, What about this. test.php <?php if(isset($_REQUEST['sqlProcess'])) { switch($_REQUEST['sqlProcess']) { case "query1": $sql=" SELECT FOO FORM BAR WHERE BAZ='BAR'" break; } $res = mysqli_query($connect,$sql); } if(!isset($res)) { $strReturn = "<form name='test' method='post' action=''> <input type='submit' name='submit' value='click' /> <input type='hidden' name='sqlProcess' value='query1' /> </form>" } else { $strReturn = "do whatever want to with your mysql result"; } echo $strReturn; ?> Hope helps. To ajaxing this page please look www.xajaxproject.org Regards On Wednesday 11 July 2007 01:59:42 k w wrote: > I'm trying to make a button execute some php code when the button is > clicked. I'm not sure if it is the button i'm coding wrong or the php code. > Here is the code I am using. > > <?php > echo "<button action='<?php > mysqli_query($connect,$query)?>'Click</button>"; ?> > > I've got all my variables stored in the php page, and I know they are all > correct. But when I push the button it does nothing. I'm not quite sure > what I am doing wrong. > > I have also tried > > <input type=button value="Click" OnClick= "<?php > mysqli_query($connect,$query); ?>"> > > and > > <form onclick="<?php mysqli_query($connect,$query); ?>"> > <input type=button value="Click"> > </form> > > Obviously i'm a complete newbie. I'd appreciate any help. Thanks.

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