Re: php to generate java-script

Jas wrote:

Anyone have a good method of grabbing the current page and reading data from it? For example: <?PHP // find all form fields for current page function FindFormFields( $page ) { if( empty( $page ) ) { $data = -1; } else { if( ( $fh = @fopen( $page, "r" ) ) === FALSE ) {

    $data = -1;

} else {

    while( !feof( $fh ) ) {
     $line = fgets( $fh, 512 );
     if( eregi( "<input type=\"", $line ) ) {
      $data[] = $line;
     }
    }
    fclose( $fh );

} } return $data; } echo FindFormFields( "http://php.net" ); ?> The above code would output the following: Array (

    [0] =>    <input type="text" name="pattern" value="" size="30"

accesskey="s" />

    [1] =>    <input type="image"

) Now for the problem I am having and a description of what I am trying to accomplish: I want to dynamically generate a form and in doing so I would like to dynamically generate the following javascript features for said page - javascript form validation - javascript form field focus The problem is if I call the current page that is being generated such as <?PHP echo FindFormFields( "http://" . $_SERVER['SERVER_NAME'] . $_SERVER['REQUEST_URI'] ); ?> Not only does it take a helluva long time to load the page but it also creates a nested array with duplicate values.

I'm not surprised it's taking a while to load in your browser. I think you have a serious nested loop issue there. What you're doing is telling the PHP engine to load the same page again. When it does that it's going to call your function *again* on the same page. Rinse and repeat. But i don't understand what putting those tags in an array is going to accomplish. Perhaps there's a lot more to this, but i'd be inclined to set up my validation in a more targetted manner. brian