Re: Trying to understand sessions and using them to authenticate...
| From: | Jason Pruim | Date: | Tue, 28 Aug 2007 14:51:30 +0000 |
| Subject: | Re: Trying to understand sessions and using them to authenticate... | ||
| References: | 1 2 3 4 5 6 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-261408@lists.php.net to get a copy of this message | ||
On Aug 28, 2007, at 10:21 AM, Daniel Brown wrote:
On 8/28/07, Jason Pruim <japruim@raoset.com> wrote:I don't have phpMyAdmin installed, never saw the need to... But I'll look into it in the future. And after adding the die that you recommended, you were right, it wasn't returning any rows. So... I did some checking and it's amazing sometimes that you can't see the trees through the forrest.... a simple $user =$_POST['user']; and $pass=$_POST['pass']; and all is well. It logs into the page, now I just need to fine tune it since it doesn't like to display the actual database now, but that's something I should be able to figure out. One other question, to logout, can I just call a file that has session_destroy() and a header("Location: ???"); in it? Or should I do something else for logging out? Thanks again! Without your help... I wouldn't be able to do this! -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 3251 132nd ave Holland, MI, 49424 www.raoset.com japruim@raoset.comOn Aug 28, 2007, at 10:03 AM, Daniel Brown wrote:On 8/28/07, Jason Pruim <japruim@raoset.com> wrote: [snip]Yes it is... For now... I am just using test/test and I had a field named password in the database but thought that was messing it up, so I dropped that field and currently I am just using the e-mail field as a password. Once it works I'll change the field to a more appropriate selection with MD5 hashing, and maybe even a little salt in the hash. (Gotta add the flavor!) -- Jason Pruim Raoset Inc. Technology Manager MQC Specialist 3251 132nd ave Holland, MI, 49424 www.raoset.com japruim@raoset.com$sql = "SELECT * FROM users WHERE user='".$user."' ANDpass='".$pass."' LIMIT 0,1;";$result = mysql_query($sql) or die("Wrong data supplied ordatabase error");while($row = mysql_fetch_array($result)) {Sounds to me like you're not getting through the while() clause,meaning that there's no matching rows in the database.$sql = "SELECT * FROM login WHERE loginid='".$user."' ANDemail='".$pass."' LIMIT 0,1;";Is the password they supply in theIf you have phpMyAdmin installed on that server, J, try using the"search" tab to see if you can find that user/email combination in the database using = and not LIKE.Perhaps there's a whitespace or something of the like that'scausing it to return zero rows.Also, try doing this after the $result = mysql_query($sql); line:die("Number of rows returned by MySQL: ".mysql_num_rows($result));