Re: for loop inside a switch

From: Date: Fri, 31 Aug 2007 22:56:52 +0000
Subject: Re: for loop inside a switch
References: 1 2  Groups: php.general 
Request: Send a blank email to php-general+get-261576@lists.php.net to get a copy of this message
Sanjeev is right. You're thinking about the problem backwards. You're trying to build a Switch inside a loop. Remember, if you ever have to do some operating multiple times you're using a forloop, then the thing that you want to repeat(switch case) is INSIDE the for loop. - Dan ""Sanjeev N"" <snsanju@gmail.com> wrote in message news:46c5cacf.11bd720a.213d.3518@mx.google.com...
This will not work at all.. Instead of switch try with if condition as follows for ($i=0; $i <21; $i++) { if(faq$i == $q){
    echo $faq1;
    break;
} } Now it works.. You can write the code to display the result how you want.. but you cant write the code to write a code :) Cheers Warm Regards, Sanjeev http://www.sanchanworld.com http://webdirectory.sanchanworld.com - Submit your website URL http://webhosting.sanchanworld.com - Choose your best web hosting plan -----Original Message----- From: Hulf [mailto:ross@blue-fly.co.uk] Sent: Thursday, August 16, 2007 3:11 PM To: php-general@lists.php.net Subject: [PHP] for loop inside a switch Hi, switch ($q) { for ($i=0; $i <21; $i++) { case 'faq$i': echo $faq1; break; } } I just want to loop out a big long list of cases. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php


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