Re: Using a variable for include statement
| From: | Robert Cummings | Date: | Tue, 11 Sep 2007 17:10:40 +0000 |
| Subject: | Re: Using a variable for include statement | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-261952@lists.php.net to get a copy of this message | ||
On Tue, 2007-09-11 at 14:00 -0300, Jeff Benetti wrote:
> Sorry if this is a noob question, I have used PERL, TCL and VB but I am just
> getting into PHP. If there is a better place to ask noobie questions then
> let me know.
>
> I want to use the include statement but I want to pass the name of the file
> rather than hard code it. It seems that PHP needs the file to be in its
> defined PATH in order to do this (or am I wrong?).
>
> My code works OK if I use hard coding
>
> Example (works)
>
> include ('somefile.php')
>
> Example (doesn't work)
>
> $TheFile = "somefile.php"
>
> include ($TheFile)
>
> Am I trying to do something that is impossible?
>
> If it is a path problem then how do I get around this, I can control my
> local server config but I only have a local server for development.
If the first works, then the second will work unless you've trimmed out
some useful information for us to see... or maybe it's the lack of a
semi-colon after the assignment (but that's probably just a quick typo
mistake).
Cheers,
Rob.
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