Re: IF command
| From: | Carlos Martínez González | Date: | Fri, 19 Oct 2007 01:00:22 +0000 |
| Subject: | Re: IF command | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-263344@lists.php.net to get a copy of this message | ||
Hi, here is the code:
if ( ($component_reference != "5") AND ($component_reference != "19") ) {
echo "<li><a href=\"index.php?request=" . $request .
"\">" .
$component_name . "</a>";
}
2007/10/19, ron.php <ron.php@actsministries.org>:
> When $component_reference is 5 or 19 I don't want the echo statement to
> output to the screen. What is the correct syntax? What I have below isn't
> working. Thanks for your help. Ron
>
> if ( ($component_reference != "5") OR ($component_reference != "19") ) {
> echo "<li><a href=\"index.php?request=" . $request .
> "\">" .
> $component_name . "</a>";
> }
>
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