show required row first and then other remaining rows

Hi, Consider the following case mysql> select *from names; +----+---------+------------+ | id | name | phone | +----+---------+------------+ | 1 | sanju | 9845650000 | | 2 | sanjeev | 9972230000 | | 3 | puttu | 9900580000 | | 4 | raju | 9448110000 | +----+---------+------------+ Now I want to display the row whose name is puttu (id=3) first and then want to display other rows in order (order by name) as follows +----+---------+------------+ | id | name | phone | +----+---------+------------+ | 3 | puttu | 9900580000 | | 4 | raju | 9448110000 | | 2 | sanjeev | 9972230000 | | 1 | sanju | 9845650000 | +----+---------+------------+ Can somebody tell me is it possible. If its possible then please help me to solve this problem. Actually I am fetching all the rows from this table to my php page and there if I choose some name then that should appear at top and rest should be below in name order. Warm Regards, Sanjeev http://www.sanchanworld.com/ http://webdirectory.sanchanworld.com - Submit your website URL http://webhosting.sanchanworld.com - Choose your best web hosting plan