Re: unexpected '@' in preg_replace???

Daniel Brown wrote:

On 10/29/07, Zoltán Németh <znemeth@alterationx.hu> wrote:

hi list, I have this code:

[snip!]

Parse error: syntax error, unexpected '@' in /home/znemeth/public_html/test/pregreplacetest1.php(94) : regexp code on line 1 Fatal error: preg_replace() [<a href='function.preg-replace'>function.preg-replace</a>]: Failed evaluating code: _nemeth@moveonerelo.com_ in /home/znemeth/public_html/test/pregreplacetest1.php on line 94

[snip=again!]

    Zoltan,

    If you're using preg_replace(), where are your start and stop

characters for the pattern and subject?

    $szoveg = preg_replace('/'.$mit.'/','/'.$mire.'/',$dokumentum);

    You could otherwise try ereg_replace(); without the slashes, or do

an htmlentities($dokumentum);.

Look again and you will notice that $mit and $mire are both arrays. Also, the starting and stopping points are in the $mit array elements. The starting and stopping points are not allowed in the $mire array. This was the offending line in the code. I removed the e from the modifiers list and it started working. See if you can run the code without it.

         '/<strong[^>]*>(.*?)<\/strong>/i',      // <strong>

you missed your closing option

         '/<\/?p[^>]*>/i',                           // <P>

or maybe you should have a different entry to remove the </p> and replace it with nothing. this

         '/<p[^>]*>/i',                           // <P>

that "\n\n\t", this

         '/<\/p[^>]*>/i',                           // </P>

that '', Side note, you might want to look into using the '+' instead of the '*'. '+' = must be one or more '*' = 0 or more In some of the cases here, I see where this can bite you in the butt later. -- Jim Lucas "Some men are born to greatness, some achieve greatness, and some have greatness thrust upon them." Twelfth Night, Act II, Scene V by William Shakespeare