Re: crop an image

From: Date: Wed, 31 Oct 2007 12:18:36 +0000
Subject: Re: crop an image
References: 1 2  Groups: php.general 
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Hi everybody, I am still strugling with the crop problem. It looks like it is not possible with PHP to do an imagecopyresampled and and imagecopy on the same image. Here is what I try to do: 1: Resize image to 80px width and correct ratio 2: Crop from that image a 80x60 part Both work for themselfes, but not together. Does anybody see the problem? $outputImg = ImageCreateTrueColor($maxX, $dstY); imagecopyresampled($outputImg, $inputImg, $posX, $posY,0,0, $picX, $picY, $srcX, $srcY); $outputImg = ImageCreateTrueColor(80, 60); imagecopy($outputImg, $inputImg, 0,0 , 0, 250, $picX, $picY); If I leave the second imagecreate away, the image will be copied into the bigger size and is not 80x60. Thank you for any help. Merlin David Christopher Zentgraf schrieb:
Copying half a pixel? I dare say that's where the problem is. Chrs, Dav On 31 Oct 2007, at 19:34, Merlin wrote:
Hi there, I do have a small problem with the proportions of image copy The image is originally vertical in 100px width and 141px height. Now I want to crop it to 80 px width and 60px height. There should be no black area and the proportions should be OK. That means that I have to copy only part of the image. In this case it would be 40.5px from above (141-60 / 2 ) and until 100.5 (40.5+60). This would crop the middle part of the image. Now with imagecoyresampled I can set the starting point of 40.5px, but not the ending point. The image will have a black bottom. Here is the code I am using: imagecopyresampled($outputImg, $inputImg, 0,0, 0 , 40.5, 80, 60, $srcX, $srcY); Thank you for any hint. Maybe somebody has a good idea on how to crop that image. Best regards, Merlin -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php


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