Re: Which file called the function?
| From: | Nathan Rixham | Date: | Fri, 21 Dec 2007 13:48:19 +0000 |
| Subject: | Re: Which file called the function? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-266203@lists.php.net to get a copy of this message | ||
global.php
<?php
function myFunc($file) {
echo $file;
}
?>
one.php
<?php
include( 'global.php' );
echo 'You are in file: ';
myFunc($file = __FILE__);
?>
might work..
Christoph Boget wrote:
Let's say I have the following 3 files global.php <? function myFunc() { echo __FILE__; } ?> one.php <? include( 'global.php' ); echo 'You are in file: '; myFunc(); ?> two.php <? include( 'global.php' ); echo 'You are in file: '; myFunc(); ?> In each case, what is echoed out for __FILE__ is global.php. Apart from analyzing the debug_backtrace array, is there any way that myFunc() would display "one.php" and "two.php" respectively? thnx, Christoph