Re: looping through a $_POST variable
| From: | Richard Kurth | Date: | Mon, 31 Dec 2007 01:33:57 +0000 |
| Subject: | Re: looping through a $_POST variable | ||
| References: | 1 2 3 4 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-266417@lists.php.net to get a copy of this message | ||
looks like that is my problem it is not separating the emails
string(67) "rkurth@centurytel.net ckurth@centurytel.net tkurth@centurytel.net"
array(1) { [0]=> string(67) "rkurth@centurytel.net ckurth@centurytel.net tkurth@centurytel.net" }
$array = explode(' ', $_POST['emails']);
what should I use for spaces or next line to separate them
Okay. Now var_dump($array) and see what it has. On Sun, December 30, 2007 6:34 pm, Richard Kurth wrote://you should probably validate the emails using: http://php.net/imap_rfc822_parse_adrlist $value_sql = mysql_real_escape_string($value);When I do a var_dump($_POST['emails']); it has all the emails in it string(65) "rkurth@centurytel.net ckurth@centurytel.net tkurth@centurytel.net" I will validate the emails after I get the loop to work $memberid comes from a part of the script I did not show you $memberid =$_POST["members_id"]; safe_query is a function that I call that does query stuff function safe_query ($query = ""){//see what you have. //maybe it's not hat you think var_dump($_POST['emails']);include ("dataconf.inc.php"); dbconnect($dbname,$rootusername,$rootpassword,$roothostname); global $query_debug;if (empty($query)) { return FALSE; }if (!empty($query_debug)) { print "<pre>$query</pre>\n"; }$result = mysql_query($query) or die("Query Failed: " ."<li>errorno=".mysql_errno(). "<br>" ."<li>error=".mysql_error(). "<br><br>" ."<li>query=".$query ); return $result;}On Sun, December 30, 2007 5:29 pm, Richard Kurth wrote:text area and it will have data like many email address or just one listed with a space or on a new line. I can't seam to get the data to extract properly. I have tried this below $array = explode(' ', $_POST['emails']);I am trying to loop through a $_POST variable. It comes from aforeach ($array as $value) {
members_id = '$memberid'";$sql = "SELECT id FROM contacts where emailaddress = '$value' AND
Use '$value_sql' here.And I dunno where $memberid came from, but maybe it should be escaped as well.
$sql_result=safe_query($sql);
I'm not sure what "safe_query" is doing, and maybe you think it canescape the data you embedded into the SQL, but I don't see how you can do that... Sort of a Humpty-Dumpty problem...
$id = $row["id"]; $sql1="UPDATE contacts SET emailstatus ='Unsubscribed' WHERE id = '$id'"; safe_query($sql1); }}while ($row=mysql_fetch_array($sql_result)){