Re: Redirecting STDERR to a file?

On Feb 3, 2008 10:08 PM, Richard Lynch <ceo@l-i-e.com> wrote: > > > On Fri, February 1, 2008 10:58 pm, js wrote: > > Hi, > > > > I was trying to write a script in PHP that takes a program name > > as an argument and invoke it as a daemon. > > PHP provides fork(pcntl_fork), setsid(posix_setsid) and umask, > > so it was easy. > > However, I couldn't find a way to redirect STDERR a file. > > I like to have the daemon write its log to its own logfile, like > > apache and mysql do. > > > > So is there any way to accomplish that? > > Any pointers, suggestions would be greatly appreciated. > > http://php.net/set_error_handler > > You can catch (almost) all the errors and send them wherever you want. > > Or maybe you just want to write this as a shell script instead of > using PHP in the first place. :-) .... in which case.... #!/bin/bash # Name: daemonize.sh (chmod 755) # Run as: sh daemonize.sh [PROG_TO_DAEMONIZE] [LOG_FILE] # Daniel P. Brown <parasane@gmail.com> # To disable logging, just use /dev/null as LOG_FILE if [ "$1" == "" ]; then echo "Missing PROG_TO_DAEMONIZE" echo "Usage: $0 [PROG_TO_DAEMONIZE] [LOG_FILE]" exit 1 fi if [ "$2" == "" ]; then echo "Missing LOG_FILE (if you don't want logging, use /dev/null)" echo "Usage: $0 [PROG_TO_DAEMONIZE] [LOG_FILE]" exit 1 fi exec "$1" 2>&1 >> $2 & if [ "$?" != 0 ]; then echo "There was an error daemonizing $1." if [ "$2" != "/dev/null" ]; then echo "Please check the log file ($2) for errors." fi exit 1 fi echo "Daemonized $1 with PID $! (from $0 with PID $$)." if [ "$2" != "/dev/null" ]; then echo "All output will be logged to $2." fi exit 0 -- </Dan> Daniel P. Brown Senior Unix Geek <? while(1) { $me = $mind--; sleep(86400); } ?>