Re: echo returnArray()['a']; // workaround
| From: | Nathan Rixham | Date: | Fri, 29 Feb 2008 00:18:56 +0000 |
| Subject: | Re: echo returnArray()['a']; // workaround | ||
| References: | 1 2 3 4 5 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-270669@lists.php.net to get a copy of this message | ||
Nathan Nobbe wrote:
On Thu, Feb 28, 2008 at 6:14 PM, Nathan Rixham <nrixham@gmail.com> wrote:don't say I didn't warn ya fellow nathan! #!/usr/bin/php <?php function sillyFunc() { return array('a' => 1, 'b' => 2, 'c' => 3, 'd' => 4, 'e'=>'some string'); } echo !${~${''}='sillyFunc'}=&${''}().${~${''}}['e'] . PHP_EOL; --- output --- some string To make things a little weirder yet here's the var's lol: print_r(get_defined_vars());if I show you guys how to do this: echo sillyFunc()['a'] . PHP_EOL; using a few brackets and things do you promise not to laugh? *it's a bit weird*id like to see it. -nathan
[] => sillyFunc
[¹] => Array
(
[a] => 1
[b] => 2
[c] => 3
[d] => 4
[e] => some string
)
to reference the var holding "string sillyFunc" (any of):
echo ${''}; echo ${NULL}; echo ${FALSE};
to reference our array [¹] (yeah it is called ¹)
print_r(${~${''}});
here's a quick simplification + alternatives.
echo (!$array = sillyFunc()),$array['e'];
echo (!$array = sillyFunc()).$array['e'];
and a useful ternary one:
echo is_array($array = sillyFunc()) ? $array['e'] : '';
told you it was a bit weird [took me a couple hours to figure out]!
nath :)