Re: Variable post as array

That is the problem, i can see the name of the file with $txtPhoto['name'] but when i use the same with temp_name, i get nothing, one weird thing is this [error] => 0 [size] => 17008 , what is that? this is the code that is giving the problem $txtPhotoData = addslashes(fread(fopen($txtPhoto, "r"), filesize($txtPhoto))); And this is the error Warning: fopen() expects parameter 1 to be string, array given in > /usr/www/users/zululr/marketplace/myzululand/specials_proc.php on line 49 I did not do the code im just trying to help out, if never use this kind of code to work with photos, i normally use move_uploaded_file and put the path in the databse, but it look like this code puts the photo in the database as binary or something. "Colin Guthrie" <gmane@colin.guthr.ie> wrote in message news:fqm3de$6k1$1@ger.gmane.org... > Pieter du Toit wrote: >> I ran a print_r on it and this is the results >> >> Array ( [txtPhoto] => Array ( [name] => g1.jpg [type] => image/pjpeg >> [tmp_name] => /tmp/php3qkA4A [error] => 0 [size] => 17008 ) ) >> >> The image received here must be inserted into a database as binary it >> looks >> like it. > > "on it" is very vague dude. Be more specific... show code!!! > > From later posts it appears you are using register_globals to access the > file as if it is a local variable. > > $txtPhotoData = addslashes(fread(fopen($txtPhoto, "r"), > filesize($txtPhoto))); > > For file upload elements $txtPhoto will be an array. use > $txtPhoto['tmp_name'] or something. It's all in the manual. > > PS just avoid register globals anyway, it's evil. > > Col >