Re: Fastest way to get table records' number
| From: | It Maq | Date: | Wed, 19 Mar 2008 17:38:16 +0000 |
| Subject: | Re: Fastest way to get table records' number | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-271839@lists.php.net to get a copy of this message | ||
Hi,
did you try mysql_num_rows ?
--- Andrew Ballard <aballard@gmail.com> wrote:
> On Wed, Mar 19, 2008 at 1:04 PM, TG
> <tg-php@gryffyndevelopment.com> wrote:
> >
> > It seems that count(*) pulls all the data from
> the row then performs a count
> > increment whereas count(did) only pulls the 'did'
> column.
>
> Again, I don't believe COUNT(*) pulls any data. If
> there is a row, it
> simply counts it. The row could be full of NULLS (if
> allowed by your
> schema - yikes) and it will still be counted. I'd
> guess that COUNT(1)
> does the same thing. COUNT(did) does only examine
> the
did column,
> but NULL values are excluded from the count.
>
> > I wonder if count(did) is the same speed as
> count(1) or if it will depend on
> > how much/what type of data is in 'did'.
> >
> >
> > I also wonder why count() takes a parameter.
> Isn't it always going to count
> > +1 for the row? I'll have to look that up
> sometime.
>
> It takes a parameter because it depends on what you
> want to count.
> COUNT(*) will return the number of rows matching the
> WHERE clause.
> COUNT(column_name) will return the number of
> non-NULL values in the
> column column_name. You could have a million rows
> in the table, but
> if every row has NULL in column_name, the COUNT()
> will return 0.
> There is also COUNT(DISTINCT column_name), which
> counts the number
> of distinct, non-NULL values in the column.
>
> Andrew
>
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