Re: Date math

(top-posting!) Add either the round function or ceil function. On Mar 25, 2008, at 6:47 AM, Ron Piggott <ron.php@actsministries.org> wrote:

Could someone then help me modify the PHP script so I won't have this timezone issue? I don't understand from looking at the date page on the PHP web site the change(s) I need to make. Thanks, Ron <? $date1 = strtotime($date1); $date2 = strtotime($date2); $factor = 86400; $difference = (($date1 - $date2) / $factor); On Mon, 2008-03-24 at 07:24 -0700, Jim Lucas wrote:

Ron Piggott wrote:

I have this math equation this list helped me generate a few weeks ago. The purpose is to calculate how many days have passed between 2 dates. Right now my output ($difference) is 93.9583333333 days. I am finding this a little weird. Does anyone see anything wrong with the way this is calculated: $date1 = strtotime($date1); (March 21st 2008) $date2 = strtotime($date2); (December 18th 2007) echo $date1 => 1206072000 echo $date2 => 1197954000 #86400 is 60 seconds x 60 minutes x 24 hours (in other words 1 days worth of seconds) $factor = 86400; $difference = (($date1 - $date2) / $factor);

As Casey suggested, it is a timestamp issue. Checkout my test script. http://www.cmsws.com/examples/php/testscripts/ron.php@actsministries.org/0001.php <plaintext><?php $date1 = strtotime('March 21st 2008'); //(March 21st 2008) echo "date1 = {$date1}\n"; $date2 = strtotime('December 18th 2007'); //(December 18th 2007) echo "date2 = {$date2}\n"; $date1 = 1206072000; echo date('c', $date1)."\n"; $date2 = 1197954000; echo date('c', $date2)."\n"; #86400 is 60 seconds x 60 minutes x 24 hours (in other words 1 days worth of seconds) $factor = 86400; $difference = (($date1 - $date2) / $factor); echo $difference."\n";

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