Re: ++ BUG??

> > whether there's a bug there or not, it's ambiguous code. You're doing two > > assignments to $idx on the same line. $idx+1 and $idx++ are NOT equivalent. > > $idx = ($idx+1)%2 is better code and you don't have to worry about the bug. > > > > Now, normally I don't argue in a public forum, but the PHP manual does say > "C-style pre- and post-increment and decrement operators". IIRC, C would > assign to the variable and then increment it. There should be no > ambiguity. Please correct me if I'm wrong. yes, foo($i++) should do foo($i) and then do $i = $i + 1. However, foo($i+1) should do foo($i+1) and increment $i. So $i+1 and $i++ are not equivalent. see what I mean? so trying to do $i = ($i++)%2 is doing two assignments to $i. One is the $i = ... part and the other is the $i++ part. That's where it gets ambiguous. I'd say this isn't a bug, but more along the lines of 'undefined behavior'.