Re: Date comparison Question

On Mon, Apr 7, 2008 at 11:42 AM, <admin@buskirkgraphics.com> wrote: >t the data is fed from the database, CaldTime is timestamp and since it will not allow me to have 2 timestamps in > the same table ?? What database are you using? It sounds like it has a specific meaning of "timestamp" - probably "the last time this row was modified" - and you want an arbitrary date column, which would probably be a different column type. Not a string, though. An actual date type. possible names are date, datetime, datestamp... , and you I set the CallEnd varchar(12). Storing the data they seem to be the same for output. I checked hexadecimal and binary to look for obscurities. > > > $sqldata['CaldTime'] = "2008-04-07 11:15:32"; > $sqldata['CallEnd'] = "2008-04-07 11:17:17"; > > $time1 = strtotime("$sqldata[CaldTime]"); > $time2 = strtotime("$sqldata[CallEnd]"); > $interval = $time2 - $time1; > > echo $interval; > > +++++++++++++++++++++++++++++++++++++++++++++++++++++++ > Displays like 1.75:0 > I am looking for a more precise time like 1:45 instead. > Am I looking at this all wrong for time difference? strtotime returns an integer number of seconds. The difference between $time1 and $time2 is 105. If you want minutes and seconds, you have to do the math yourself. $interval_min = floor($interval/60); $interval_sec = $interval % 60; echo "$interval_min:$interval_sec"; -- Mark J. Reed <markjreed@mail.com>