Re: Syntax error
| From: | Folke Ashberg | Date: | Tue, 28 Nov 2000 00:01:51 +0000 |
| Subject: | Re: Syntax error | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-27510@lists.php.net to get a copy of this message | ||
Hi!
the syntax is
for($x=0;$x<3;$x++)
{
//foo
}
it looks then:
while($row=mysql_fetch_row($resulta))
{$x = $row[1];
echo $x;
for($i=0;$i<strlen($x);$i++)
{
echo $i;
if ((substr($x,$i,1)==(substr($winner,$i,1))
{
$y++;
echo $y;}
}}
regards
Folke
--
Folke Ashberg
Stage Internet Services GmbH
Technical Development
folke@fanstage.de
folke@fanstage.de | Tel: +49 89 454591-77 | Fax: +49 89 454591-71
Kreillerstr. 21 | 81673 Munich | Germany | www.fanstage.de
On Mon, 27 Nov 2000, Mike P wrote:
> I keep getting a syntax error on line 25($y++).Ive tried every thing.I would
> appreciate some help and some insight into the nesting rules.
> $winner=111110011100111;
> $y=0;
> mysql_connect ("localhost","mpeloso","ampeloso")
> or die("a");
> mysql_select_db("ampsoft_com")
> or die("b");
> $resulta = mysql_query("Select User,Picks from Picks");
> while($row=mysql_fetch_row($resulta))
> {$x = $row[1];
> echo $x;
> {for($i=0;$i<strlen($x);$i++)
> echo $i;
> {if ((substr($x,$i,1)==(substr($winner,$i,1))
> $y++;
> echo $y;}
> }}
>
>
> mpeloso@princeton.edu
>
>
>
>