Re: Question before I end up writing alot of extra code...

From: Date: Mon, 07 Jul 2008 20:22:20 +0000
Subject: Re: Question before I end up writing alot of extra code...
References: 1 2 3  Groups: php.general 
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please oh please also run that through filter_input() before throwing a $_POST directly into the db query ;p On 7/7/08, Shawn McKenzie <nospam@mckenzies.net> wrote: > Jason Pruim wrote: > > > > MAIN PAGE: > > <?PHP > > > > echo $row['Tab']; //what do you get? > > > if($row['Tab'] == "done"){ > > $Tchecked1 = "CHECKED"; > > $Tchecked2 = NULL; > > }else{ > > $Tchecked1 = NULL; > > $Tchecked2 = "CHECKED"; > > } > > > > echo" > > <fieldset>Tab<BR> > > <input type="radio" name="rdoTab" value="done" > > $Tchecked1>Done <BR> > > <input type="radio" name="rdoTab" value="on" > > $Tchecked2>Not Done<BR> > > </fieldset>"; > > ?> > > PROCESSING: > > <?PHP > > > > print_r($_POST); //what do you get? > > > $tab = $_POST['rdoTab']; > > $record = $_POST['txtRecord']; > > $updateQuery = "UPDATE current SET > > Tab='$tab' WHERE > Record='$record'"; > > mysqli_real_query($link, $updateQuery); > > ?> > > > > You're saying now that that record now has field Tab=''? > > -Shawn > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php > >

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