Re: Need help with regular expression

Your description of the problem is confusing. Do you simply want to delete a table row if it contains a variable, e.g., $var='bigfoto' and append "==REPLACEMENT==" ? Where $var can be anything you assign. Maxim Antonov wrote:

Hello. But I need no td and tr inside regular expression It is a part of my templater. In real code it looks like: if(strlen($item[$key])<1){

                return preg_replace('#\{%%%.*?\{%'.$key.'%\}.*?%%%\}#is','',$tpl);
            }

if one of $key inside {%%% .... %%%} points to empty array item - all section between {%%% %%%} must be deleted. Daniel Brown :

On Wed, Jul 9, 2008 at 5:21 AM, Maxim Antonov <max@maxantonov.name> wrote:

Hi, all! I try to use folowing regular expression: $out = preg_replace('#\{%%%.*?\{%bigfoto%\}.*?%%%\}#is','==REPLACEMENT==',$str);

[snip!]

I need result as: <tr><td>NAME:</td><td><input type="text" name="name" value="" size="80"/></td></tr> <tr><td>Foto:</td><td><input type="file" name="foto" value="{%foto%}" /> {%%%<br/><img alt="{%name%}" src="{%foto%}"/>%%%} </td></tr> ==REPLACEMENT==

[snip!]

    To get it *exactly* as you've mentioned here, use this instead:

<?php $out = preg_replace('/<tr><td>Big.*\{%%%.*\{%bigfoto%\}.*%%%\}.*<\/tr>/Uis','==REPLACEMENT==',$str); ?>