Re: newbie Q: How to say, "if the fileNAME is equal to...", or better yet, "if the fileNAME ends with '.jpg'"?
| From: | James Ausmus | Date: | Tue, 26 Aug 2008 16:15:10 +0000 |
| Subject: | Re: newbie Q: How to say, "if the fileNAME is equal to...", or better yet, "if the fileNAME ends with '.jpg'"? | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-278732@lists.php.net to get a copy of this message | ||
On Tue, Aug 26, 2008 at 8:57 AM, Ford, Mike <M.Ford@leedsmet.ac.uk> wrote:
> On 25 August 2008 00:54, Govinda advised:
<snip>
> Personally, I might be tempted to do something like this:
>
> if (($pos = strrchr($file, '.'))!==FALSE):
> switch (strtolower(substr($file, $pos))):
> case '.gif':
> case '.png':
> case '.jpg':
> case '.jpeg':
> echo $file;
> endswitch;
> endif;
<snip>
Of course, this could be simplified *slightly* by actually taking
advantage of the loose typing of PHP - change the above if statement
to:
if (($pos = strpos($file, '.')))
{
$restOfAboveCodeHere;
}
This way, if the file is the '.' or '..' files, then you will get a 0
for the position of the '.', which will evaluate to FALSE. All other
files will return a non-zero position of the '.' char, which will
evaluate to TRUE. Also, I would believe (but have no evidence at all
of) that a forward-looking string position search will be very
slightly faster than a strrchr search - dunno for certain, and don't
care enough to code up a couple-line test, but just my gut... ;)
-James