Re: strings

From: Date: Fri, 01 Dec 2000 02:07:47 +0000
Subject: Re: strings
References: 1  Groups: php.general 
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Well, thanks for the responses. I went back and checked it, and when i change the var name to $ds[$i] instead of $d[$i], it also worked as it should. Strange, i have no idea why this had this problem, and wondered of the var "$d" had some strange connection to it, but clearly it does not according to your results. thanks for the input. On Thu, 30 Nov 2000, Philip Hallstrom wrote: > I just did the following (don't have get_next_month) and it works like > it should. This is on 4.0.2 > > <?php > $day[$i] = "2000-11-30"; > $day[$i] .= "-"; > $item = explode("-", $day[$i]); > $y[$i] = $item[0]; > $m[$i] = $item[1]; > $d[$i] = $item[2]; > print "Stored $i: m=$m[$i],d=$d[$i],y=$y[$i] == $day[$i]"; > ?> > > In article <Pine.OSF.4.30.0011301412170.899-100000@ewald.mbi.ucla.edu> you write: > > > >Hi, I am confused why the following does not work: > > > ><snip> > > $day[$i] = mysql_result($r,$j,"day"); > > $day[$i] .= "-"; > > $item = explode("-", $day[$i]); > > $y[$i] = $item[0]; > > $m[$i] = get_next_month($item[1]); > > $d[$i] = $item[2]; > >print "Stored $i: m=$m[$i],d=$d[$i],y=$y[$i] == $day[$i]"; > ><snip> > > > >prints: > >Stored 0: m=Nov,d=3,y=2000 == 2000-11-30- > > > >my question is: why does the $d[$i] var only get only number, 3, instead > >of 30, when the $y[$i] var gets all four, or 2000? > > > >TIA > >-tom > > > > > > > >-- > >PHP General Mailing List (http://www.php.net/) > >To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net > >For additional commands, e-mail: php-general-help@lists.php.net > >To contact the list administrators, e-mail: php-list-admin@lists.php.net > > > >

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