Re: Binary file copy
| From: | Nathan Rixham | Date: | Thu, 16 Oct 2008 18:02:04 +0000 |
| Subject: | Re: Binary file copy | ||
| References: | 1 | Groups: | php.general |
| Request: | Send a blank email to php-general+get-281994@lists.php.net to get a copy of this message | ||
Jay Moore wrote:
Greetings list! Say I want to copy a jpg from a remote server onto mine, using PHP. Right now, my script opens a socket to the remote server, and opens the image file. It copies its contents into a dummy variable, opens a new file on my server, and dumps the contents of the dummy variable into the new file. For reasons I cannot figure out, it is not working the way I want. Rather than display the image, I get an nothing when opening it in an image viewer. Code follows: ------ <?php $ip = '10.10.10.3'; $port = '80'; $h = @fsockopen($ip, $port, $err, $str, 5); if ($h) {in the response you'll be getting the raw http response (including headers); so you're saving them as well thus not a valid image file. can't see why: $image = file_get_contents('http://10.10.10.3/record/current.jpg'); wouldn't work for you.. regardless though if you are using sockets, be sure to trim of that raw http response - oh and look out for chunked or encoded file transfer as well as you'll need to decode etc etc.. (large can of worms - use an http transport class)// Get current image $h = @fsockopen($ip, $port, $err, $str, 5); $out = "GET /record/current.jpg HTTP/1.1\r\n"; $out .= "Host: $ip\r\n"; $out .= "Connection: Close\r\n\r\n"; fputs($h, $out, strlen($out)); $data = ''; while (!feof($h)) { $data .= fgets($h, 128); } fclose($h); // Store to file $f = fopen('/path/test.jpg', "wb"); if ($f) { fwrite($f, $data, strlen($data)); fclose($f); } else { die('cannot open file for writing'); }} else {die('cannot contact server');} ?> --------- I have trimmed the code some, and omitted the part where I remove the HTTP headers and other information I do not need. Why isn't this working for me? Thanks in advance, Jay