Array vs. Scalar Lists

I was wondering if there's a way to pass array keys implicitly to a function that expects a list of scalars. I'm used to perl's method of handling arrays as lists of scalars. If I wanted to print the concatenated contents of an array, I would just pass the entire array. If I did this with echo, I get the word "Array" (no real surprise). Now, I understand how to extract all of the values out of the array and pass them as one string, like: echo implode ( '', $arrayOfStrings ) ; That would accomplish the task, but not the way I would like. I'm just using echo as an example. So, I want to _simulate_ the following: echo $arrayOfStrings[0], $arrayOfStrings[1], $arrayOfStrings[2] ; The problem with the above statement is that if $arrayOfStrings[3] exists, it's not printed. I found a way to do it with eval(), and it works to my satisfaction because I'm not actually imploding the values, just the keys of the array in the proper syntax: $stmt = 'echo ' ; foreach ( $arrayOfStrings as $key => $val ) { if ( next ( $strings ) ) { $stmt .= "\$arrayOfStrings[$key], " ; } else { $stmt .= "\$arrayOfStrings[$key] ;" ; } } eval ( $stmt ) ; I'm sure I could have used another function like array_keys(), but it helps to get the keys one at a time so I can add the correct syntax. But is there a way to do this without eval()? Anthony