Re: array in the class

There's not a problem... let me trace through it for you; hopefully that'll help. : $a= new Sample("One"); : $b= new Sample("Two"); : $c= new Sample("Three"); : : $a->set_parsed(array($b)); : $b->set_parsed(array($c)); : : $a->print_me(); OK, it's obvious that the objects $a, $b, and $c are created. At this point, they all have empty arrays in their $parsed elements. When you run $a->set_parsed(array($b)), $b is copied to a new object (let's call it $z), which is also an instance of the class Sample. So now $a->parsed = Array( $z ), and $z->name = "Two", $z->parsed = Array( ). Then we run $b->set_parsed(array($c)). Again, a new Sample object (this time $y) is created with the same member values as $c; that is, $y->name = "Three", and $y->parsed = Array( ). So now when we run $a->print_me(), your recursive function is called: function print_me() { for (reset($this->parsed);$tmp=current($this->parsed);next($this->parsed)){ $tmp->print_me(); } print "Name: $this->name <br>\n "; } $a->print_me() first traverses its $a->parsed array. The array contains only the element ($z). $z->print_me() runs. $z->parsed has no elements, so the for loop's condition fails immediately and the for loop never runs. Then $z->name (which was "Two") is printed. Execution returns back to the prior instance of print_me(), $a->print_me(). This function has now completely traversed its array (it only had one element) and the for loop is completed. $a->name (which was "One") is printed, and the original function called is finished; execution returns back to the next line after the function call, and, in this case, stops... Toby Butzon [ criticism spurs improvement ] ----- Original Message ----- From: "arnost" <arnost@cs.cas.cz> To: <php-general@lists.php.net> Sent: Saturday, December 02, 2000 7:37 AM Subject: [PHP] array in the class : hi, : : I have defined container class Sample: : : : class Sample { : var $name; : var $parsed = array(); : : function Sample ($name) : { : $this->name = $name; : } : : function set_parsed($parsed) : { : $this->parsed=$parsed; : } : : function print_me() : { : for (reset($this->parsed);$tmp=current($this->parsed);next($this->parsed)){ : $tmp->print_me(); : } : print "Name: $this->name <br>\n "; : } : } : : : Now I try sample usage: : : : $a= new Sample("One"); : $b= new Sample("Two"); : $c= new Sample("Three"); : : $a->set_parsed(array($b)); : $b->set_parsed(array($c)); : : $a->print_me(); : : : which print the strange result: : : Name: Two : Name: One : : : but when I switch the set_parsed calls: : : $a= new Sample("One"); : $b= new Sample("Two"); : $c= new Sample("Three"); : : $b->set_parsed(array($c)); : $a->set_parsed(array($b)); : : $a->print_me(); : : I obtain right (imho) result: : : Name: Three : Name: Two : Name: One : : : Where is the problem? : : I use PHP Version 4.0.1pl2. : : thanks : : : -- : Arnost Stedry : Ustav informatiky : : : -- : PHP General Mailing List (http://www.php.net/) : To unsubscribe, e-mail: php-general-unsubscribe@lists.php.net : For additional commands, e-mail: php-general-help@lists.php.net : To contact the list administrators, e-mail: php-list-admin@lists.php.net : :